(3x^2-11x-4)/(x^2+x-20)

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Solution for (3x^2-11x-4)/(x^2+x-20) equation: 


D( x )

x^2+x-20 = 0

x^2+x-20 = 0

x^2+x-20 = 0

x^2+x-20 = 0

DELTA = 1^2-(-20*1*4)

DELTA = 81

DELTA > 0

x = (81^(1/2)-1)/(1*2) or x = (-81^(1/2)-1)/(1*2)

x = 4 or x = -5

x in (-oo:-5) U (-5:4) U (4:+oo)

(3*x^2-(11*x)-4)/(x^2+x-20) = 0

(3*x^2-11*x-4)/(x^2+x-20) = 0

3*x^2-11*x-4 = 0

3*x^2-11*x-4 = 0

DELTA = (-11)^2-(-4*3*4)

DELTA = 169

DELTA > 0

x = (169^(1/2)+11)/(2*3) or x = (11-169^(1/2))/(2*3)

x = 4 or x = -1/3

(x+1/3)*(x-4) = 0

x^2+x-20 = 0

x^2+x-20 = 0

DELTA = 1^2-(-20*1*4)

DELTA = 81

DELTA > 0

x = (81^(1/2)-1)/(1*2) or x = (-81^(1/2)-1)/(1*2)

x = 4 or x = -5

(x+5)*(x-4) = 0

((x+1/3)*(x-4))/((x+5)*(x-4)) = 0

( x+1/3 )

x+1/3 = 0 // - 1/3

x = -1/3

( x-4 )

x-4 = 0 // + 4

x = 4

x in { 4} 

x = -1/3

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